2(5b+1)=7b-13

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Solution for 2(5b+1)=7b-13 equation: 



2(5b+1)=7b-13

We move all terms to the left:

2(5b+1)-(7b-13)=0

We multiply parentheses

10b-(7b-13)+2=0

We get rid of parentheses

10b-7b+13+2=0

We add all the numbers together, and all the variables

3b+15=0

We move all terms containing b to the left, all other terms to the right

3b=-15

b=-15/3

b=-5

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