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2(5c+1)-53=4c+3
We move all terms to the left:
2(5c+1)-53-(4c+3)=0
We multiply parentheses
10c-(4c+3)+2-53=0
We get rid of parentheses
10c-4c-3+2-53=0
We add all the numbers together, and all the variables
6c-54=0
We move all terms containing c to the left, all other terms to the right
6c=54
c=54/6
c=9
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