2(5c+2)+2c=3(2c+3)+7

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Solution for 2(5c+2)+2c=3(2c+3)+7 equation:


Simplifying
2(5c + 2) + 2c = 3(2c + 3) + 7

Reorder the terms:
2(2 + 5c) + 2c = 3(2c + 3) + 7
(2 * 2 + 5c * 2) + 2c = 3(2c + 3) + 7
(4 + 10c) + 2c = 3(2c + 3) + 7

Combine like terms: 10c + 2c = 12c
4 + 12c = 3(2c + 3) + 7

Reorder the terms:
4 + 12c = 3(3 + 2c) + 7
4 + 12c = (3 * 3 + 2c * 3) + 7
4 + 12c = (9 + 6c) + 7

Reorder the terms:
4 + 12c = 9 + 7 + 6c

Combine like terms: 9 + 7 = 16
4 + 12c = 16 + 6c

Solving
4 + 12c = 16 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
4 + 12c + -6c = 16 + 6c + -6c

Combine like terms: 12c + -6c = 6c
4 + 6c = 16 + 6c + -6c

Combine like terms: 6c + -6c = 0
4 + 6c = 16 + 0
4 + 6c = 16

Add '-4' to each side of the equation.
4 + -4 + 6c = 16 + -4

Combine like terms: 4 + -4 = 0
0 + 6c = 16 + -4
6c = 16 + -4

Combine like terms: 16 + -4 = 12
6c = 12

Divide each side by '6'.
c = 2

Simplifying
c = 2

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