2(5c+2)-2c=3(2c+3)+17

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Solution for 2(5c+2)-2c=3(2c+3)+17 equation: 



2(5c+2)-2c=3(2c+3)+17

We move all terms to the left:

2(5c+2)-2c-(3(2c+3)+17)=0

We add all the numbers together, and all the variables

-2c+2(5c+2)-(3(2c+3)+17)=0

We multiply parentheses

-2c+10c-(3(2c+3)+17)+4=0



We calculate terms in parentheses: -(3(2c+3)+17), so:

3(2c+3)+17

We multiply parentheses

6c+9+17

We add all the numbers together, and all the variables

6c+26

Back to the equation:

-(6c+26)



We add all the numbers together, and all the variables

8c-(6c+26)+4=0

We get rid of parentheses

8c-6c-26+4=0

We add all the numbers together, and all the variables

2c-22=0

We move all terms containing c to the left, all other terms to the right

2c=22

c=22/2

c=11

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