2(5c+2)-2c=3(2c+3)=7

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Solution for 2(5c+2)-2c=3(2c+3)=7 equation:



2(5c+2)-2c=3(2c+3)=7
We move all terms to the left:
2(5c+2)-2c-(3(2c+3))=0
We add all the numbers together, and all the variables
-2c+2(5c+2)-(3(2c+3))=0
We multiply parentheses
-2c+10c-(3(2c+3))+4=0
We calculate terms in parentheses: -(3(2c+3)), so:
3(2c+3)
We multiply parentheses
6c+9
Back to the equation:
-(6c+9)
We add all the numbers together, and all the variables
8c-(6c+9)+4=0
We get rid of parentheses
8c-6c-9+4=0
We add all the numbers together, and all the variables
2c-5=0
We move all terms containing c to the left, all other terms to the right
2c=5
c=5/2
c=2+1/2

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