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2(5c+2-2c)=3(2c+3+7)
We move all terms to the left:
2(5c+2-2c)-(3(2c+3+7))=0
We add all the numbers together, and all the variables
2(3c+2)-(3(2c+10))=0
We multiply parentheses
6c-(3(2c+10))+4=0
We calculate terms in parentheses: -(3(2c+10)), so:We get rid of parentheses
3(2c+10)
We multiply parentheses
6c+30
Back to the equation:
-(6c+30)
6c-6c-30+4=0
We add all the numbers together, and all the variables
-26!=0
There is no solution for this equation
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