2(5c+4)-10=8c-(3c+5)

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Solution for 2(5c+4)-10=8c-(3c+5) equation: 



2(5c+4)-10=8c-(3c+5)

We move all terms to the left:

2(5c+4)-10-(8c-(3c+5))=0

We multiply parentheses

10c-(8c-(3c+5))+8-10=0



We calculate terms in parentheses: -(8c-(3c+5)), so:

8c-(3c+5)

We get rid of parentheses

8c-3c-5

We add all the numbers together, and all the variables

5c-5

Back to the equation:

-(5c-5)



We add all the numbers together, and all the variables

10c-(5c-5)-2=0

We get rid of parentheses

10c-5c+5-2=0

We add all the numbers together, and all the variables

5c+3=0

We move all terms containing c to the left, all other terms to the right

5c=-3

c=-3/5

c=-3/5

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