2(5c-2)-2c=3(2c+3)+7

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Solution for 2(5c-2)-2c=3(2c+3)+7 equation:



2(5c-2)-2c=3(2c+3)+7
We move all terms to the left:
2(5c-2)-2c-(3(2c+3)+7)=0
We add all the numbers together, and all the variables
-2c+2(5c-2)-(3(2c+3)+7)=0
We multiply parentheses
-2c+10c-(3(2c+3)+7)-4=0
We calculate terms in parentheses: -(3(2c+3)+7), so:
3(2c+3)+7
We multiply parentheses
6c+9+7
We add all the numbers together, and all the variables
6c+16
Back to the equation:
-(6c+16)
We add all the numbers together, and all the variables
8c-(6c+16)-4=0
We get rid of parentheses
8c-6c-16-4=0
We add all the numbers together, and all the variables
2c-20=0
We move all terms containing c to the left, all other terms to the right
2c=20
c=20/2
c=10

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