2(5c-7)=10(c-3)

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Solution for 2(5c-7)=10(c-3) equation: 



2(5c-7)=10(c-3)

We move all terms to the left:

2(5c-7)-(10(c-3))=0

We multiply parentheses

10c-(10(c-3))-14=0



We calculate terms in parentheses: -(10(c-3)), so:

10(c-3)

We multiply parentheses

10c-30

Back to the equation:

-(10c-30)



We get rid of parentheses

10c-10c+30-14=0

We add all the numbers together, and all the variables

16!=0

There is no solution for this equation

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