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2(5c-70)=10(c-3)
We move all terms to the left:
2(5c-70)-(10(c-3))=0
We multiply parentheses
10c-(10(c-3))-140=0
We calculate terms in parentheses: -(10(c-3)), so:We get rid of parentheses
10(c-3)
We multiply parentheses
10c-30
Back to the equation:
-(10c-30)
10c-10c+30-140=0
We add all the numbers together, and all the variables
-110!=0
There is no solution for this equation
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