2(5d+2)-2d=3(2d+3)+7

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Solution for 2(5d+2)-2d=3(2d+3)+7 equation: 



2(5d+2)-2d=3(2d+3)+7

We move all terms to the left:

2(5d+2)-2d-(3(2d+3)+7)=0

We add all the numbers together, and all the variables

-2d+2(5d+2)-(3(2d+3)+7)=0

We multiply parentheses

-2d+10d-(3(2d+3)+7)+4=0



We calculate terms in parentheses: -(3(2d+3)+7), so:

3(2d+3)+7

We multiply parentheses

6d+9+7

We add all the numbers together, and all the variables

6d+16

Back to the equation:

-(6d+16)



We add all the numbers together, and all the variables

8d-(6d+16)+4=0

We get rid of parentheses

8d-6d-16+4=0

We add all the numbers together, and all the variables

2d-12=0

We move all terms containing d to the left, all other terms to the right

2d=12

d=12/2

d=6

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