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2(5d+4)=1/4(9+d)
We move all terms to the left:
2(5d+4)-(1/4(9+d))=0
Domain of the equation: 4(9+d))!=0We add all the numbers together, and all the variables
d∈R
2(5d+4)-(1/4(d+9))=0
We multiply parentheses
10d-(1/4(d+9))+8=0
We multiply all the terms by the denominator
10d*4(d+9))-(1+8*4(d+9))=0
Wy multiply elements
40d^2(d+32d(d=0
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