2(5e+2)-2e=3(2e+3)+7

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Solution for 2(5e+2)-2e=3(2e+3)+7 equation: 



2(5e+2)-2e=3(2e+3)+7

We move all terms to the left:

2(5e+2)-2e-(3(2e+3)+7)=0

We add all the numbers together, and all the variables

-2e+2(5e+2)-(3(2e+3)+7)=0

We multiply parentheses

-2e+10e-(3(2e+3)+7)+4=0



We calculate terms in parentheses: -(3(2e+3)+7), so:

3(2e+3)+7

We multiply parentheses

6e+9+7

We add all the numbers together, and all the variables

6e+16

Back to the equation:

-(6e+16)



We add all the numbers together, and all the variables

8e-(6e+16)+4=0

We get rid of parentheses

8e-6e-16+4=0

We add all the numbers together, and all the variables

2e-12=0

We move all terms containing e to the left, all other terms to the right

2e=12

e=12/2

e=6

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