2(5f+2)+f=2(2f-5)-7

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Solution for 2(5f+2)+f=2(2f-5)-7 equation: 


Simplifying
2(5f + 2) + f = 2(2f + -5) + -7

Reorder the terms:
2(2 + 5f) + f = 2(2f + -5) + -7
(2 * 2 + 5f * 2) + f = 2(2f + -5) + -7
(4 + 10f) + f = 2(2f + -5) + -7

Combine like terms: 10f + f = 11f
4 + 11f = 2(2f + -5) + -7

Reorder the terms:
4 + 11f = 2(-5 + 2f) + -7
4 + 11f = (-5 * 2 + 2f * 2) + -7
4 + 11f = (-10 + 4f) + -7

Reorder the terms:
4 + 11f = -10 + -7 + 4f

Combine like terms: -10 + -7 = -17
4 + 11f = -17 + 4f

Solving
4 + 11f = -17 + 4f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-4f' to each side of the equation.
4 + 11f + -4f = -17 + 4f + -4f

Combine like terms: 11f + -4f = 7f
4 + 7f = -17 + 4f + -4f

Combine like terms: 4f + -4f = 0
4 + 7f = -17 + 0
4 + 7f = -17

Add '-4' to each side of the equation.
4 + -4 + 7f = -17 + -4

Combine like terms: 4 + -4 = 0
0 + 7f = -17 + -4
7f = -17 + -4

Combine like terms: -17 + -4 = -21
7f = -21

Divide each side by '7'.
f = -3

Simplifying
f = -3

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