2(5f-19)=10f-38

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Solution for 2(5f-19)=10f-38 equation: 


Simplifying
2(5f + -19) = 10f + -38

Reorder the terms:
2(-19 + 5f) = 10f + -38
(-19 * 2 + 5f * 2) = 10f + -38
(-38 + 10f) = 10f + -38

Reorder the terms:
-38 + 10f = -38 + 10f

Add '38' to each side of the equation.
-38 + 38 + 10f = -38 + 38 + 10f

Combine like terms: -38 + 38 = 0
0 + 10f = -38 + 38 + 10f
10f = -38 + 38 + 10f

Combine like terms: -38 + 38 = 0
10f = 0 + 10f
10f = 10f

Add '-10f' to each side of the equation.
10f + -10f = 10f + -10f

Combine like terms: 10f + -10f = 0
0 = 10f + -10f

Combine like terms: 10f + -10f = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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