2(5j+2)-3(j-4)=2(4j+5)

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Solution for 2(5j+2)-3(j-4)=2(4j+5) equation: 



2(5j+2)-3(j-4)=2(4j+5)

We move all terms to the left:

2(5j+2)-3(j-4)-(2(4j+5))=0

We multiply parentheses

10j-3j-(2(4j+5))+4+12=0



We calculate terms in parentheses: -(2(4j+5)), so:

2(4j+5)

We multiply parentheses

8j+10

Back to the equation:

-(8j+10)



We add all the numbers together, and all the variables

7j-(8j+10)+16=0

We get rid of parentheses

7j-8j-10+16=0

We add all the numbers together, and all the variables

-1j+6=0

We move all terms containing j to the left, all other terms to the right

-j=-6

j=-6/-1

j=+6

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