2(5j-3)-j=3(3j-2)

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Solution for 2(5j-3)-j=3(3j-2) equation: 



2(5j-3)-j=3(3j-2)

We move all terms to the left:

2(5j-3)-j-(3(3j-2))=0

We add all the numbers together, and all the variables

-1j+2(5j-3)-(3(3j-2))=0

We multiply parentheses

-1j+10j-(3(3j-2))-6=0



We calculate terms in parentheses: -(3(3j-2)), so:

3(3j-2)

We multiply parentheses

9j-6

Back to the equation:

-(9j-6)



We add all the numbers together, and all the variables

9j-(9j-6)-6=0

We get rid of parentheses

9j-9j+6-6=0

We add all the numbers together, and all the variables

=0

j=0/1

j=0

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