2(5k-8)-20=11(2k-3)+3k

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Solution for 2(5k-8)-20=11(2k-3)+3k equation: 



2(5k-8)-20=11(2k-3)+3k

We move all terms to the left:

2(5k-8)-20-(11(2k-3)+3k)=0

We multiply parentheses

10k-(11(2k-3)+3k)-16-20=0



We calculate terms in parentheses: -(11(2k-3)+3k), so:

11(2k-3)+3k

We add all the numbers together, and all the variables

3k+11(2k-3)

We multiply parentheses

3k+22k-33

We add all the numbers together, and all the variables

25k-33

Back to the equation:

-(25k-33)



We add all the numbers together, and all the variables

10k-(25k-33)-36=0

We get rid of parentheses

10k-25k+33-36=0

We add all the numbers together, and all the variables

-15k-3=0

We move all terms containing k to the left, all other terms to the right

-15k=3

k=3/-15

k=-1/5

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