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2(5m+3)8m=4
We move all terms to the left:
2(5m+3)8m-(4)=0
We multiply parentheses
80m^2+48m-4=0
a = 80; b = 48; c = -4;
Δ = b2-4ac
Δ = 482-4·80·(-4)
Δ = 3584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3584}=\sqrt{256*14}=\sqrt{256}*\sqrt{14}=16\sqrt{14}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-16\sqrt{14}}{2*80}=\frac{-48-16\sqrt{14}}{160} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+16\sqrt{14}}{2*80}=\frac{-48+16\sqrt{14}}{160} $
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