If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2(5r+5)=10(2r-2)
We move all terms to the left:
2(5r+5)-(10(2r-2))=0
We multiply parentheses
10r-(10(2r-2))+10=0
We calculate terms in parentheses: -(10(2r-2)), so:We get rid of parentheses
10(2r-2)
We multiply parentheses
20r-20
Back to the equation:
-(20r-20)
10r-20r+20+10=0
We add all the numbers together, and all the variables
-10r+30=0
We move all terms containing r to the left, all other terms to the right
-10r=-30
r=-30/-10
r=+3
| m/11+30=36 | | 8x+9=5x-21 | | 12x-24=6-3x | | 8x²+8x+201=0 | | 3+2p+4p=-9 | | 80-4x=48 | | 12d²+8d+201=0 | | 15=8b-1-8 | | 12x-5=6-3x | | 4=x+1-4 | | 2x+6=-4×-12 | | 8=2x/7x | | 10=a+4a | | -12=r-5r | | 8=2/7x | | x-0.15x=125 | | 174+10x-6=102+10x | | 45=7a+3 | | (3x+26)+2x+39=180 | | (6x+10)+(x+15)+(2x+20)=180 | | -5x+2x=-5 | | p^2+5p–14=0 | | 2x+10+8x-20=180 | | p2+5p–14=0 | | x-0.10x=100 | | -4(y–2)+9y=3 | | |4-4y|-10=6 | | 42w+7=13 | | 3a+2(2+3(a–1))=2((3a+4) | | 2/5(m+4)=6 | | n-3+4n=2 | | -7x+3)=21 |