2(5r+5)=10(2r-2)

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Solution for 2(5r+5)=10(2r-2) equation: 



2(5r+5)=10(2r-2)

We move all terms to the left:

2(5r+5)-(10(2r-2))=0

We multiply parentheses

10r-(10(2r-2))+10=0



We calculate terms in parentheses: -(10(2r-2)), so:

10(2r-2)

We multiply parentheses

20r-20

Back to the equation:

-(20r-20)



We get rid of parentheses

10r-20r+20+10=0

We add all the numbers together, and all the variables

-10r+30=0

We move all terms containing r to the left, all other terms to the right

-10r=-30

r=-30/-10

r=+3

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