2(5r+6)=-8(r-6)+6r

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Solution for 2(5r+6)=-8(r-6)+6r equation: 



2(5r+6)=-8(r-6)+6r

We move all terms to the left:

2(5r+6)-(-8(r-6)+6r)=0

We multiply parentheses

10r-(-8(r-6)+6r)+12=0



We calculate terms in parentheses: -(-8(r-6)+6r), so:

-8(r-6)+6r

We add all the numbers together, and all the variables

6r-8(r-6)

We multiply parentheses

6r-8r+48

We add all the numbers together, and all the variables

-2r+48

Back to the equation:

-(-2r+48)



We get rid of parentheses

10r+2r-48+12=0

We add all the numbers together, and all the variables

12r-36=0

We move all terms containing r to the left, all other terms to the right

12r=36

r=36/12

r=3

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