2(5r+60)=20(2r-12)

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Solution for 2(5r+60)=20(2r-12) equation:



2(5r+60)=20(2r-12)
We move all terms to the left:
2(5r+60)-(20(2r-12))=0
We multiply parentheses
10r-(20(2r-12))+120=0
We calculate terms in parentheses: -(20(2r-12)), so:
20(2r-12)
We multiply parentheses
40r-240
Back to the equation:
-(40r-240)
We get rid of parentheses
10r-40r+240+120=0
We add all the numbers together, and all the variables
-30r+360=0
We move all terms containing r to the left, all other terms to the right
-30r=-360
r=-360/-30
r=+12

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