2(5r-2)=3(r+3)-2

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Solution for 2(5r-2)=3(r+3)-2 equation:



2(5r-2)=3(r+3)-2
We move all terms to the left:
2(5r-2)-(3(r+3)-2)=0
We multiply parentheses
10r-(3(r+3)-2)-4=0
We calculate terms in parentheses: -(3(r+3)-2), so:
3(r+3)-2
We multiply parentheses
3r+9-2
We add all the numbers together, and all the variables
3r+7
Back to the equation:
-(3r+7)
We get rid of parentheses
10r-3r-7-4=0
We add all the numbers together, and all the variables
7r-11=0
We move all terms containing r to the left, all other terms to the right
7r=11
r=11/7
r=1+4/7

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