2(5t+1)-6=t-(t+3)

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Solution for 2(5t+1)-6=t-(t+3) equation: 



2(5t+1)-6=t-(t+3)

We move all terms to the left:

2(5t+1)-6-(t-(t+3))=0

We multiply parentheses

10t-(t-(t+3))+2-6=0



We calculate terms in parentheses: -(t-(t+3)), so:

t-(t+3)

We get rid of parentheses

t-t-3

We add all the numbers together, and all the variables

-3

Back to the equation:

-(-3)



We add all the numbers together, and all the variables

10t-1=0

We move all terms containing t to the left, all other terms to the right

10t=1

t=1/10

t=1/10

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