2(5v-4)-10(v-4)=-v+3(v-10)

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Solution for 2(5v-4)-10(v-4)=-v+3(v-10) equation: 



2(5v-4)-10(v-4)=-v+3(v-10)

We move all terms to the left:

2(5v-4)-10(v-4)-(-v+3(v-10))=0

We multiply parentheses

10v-10v-(-v+3(v-10))-8+40=0



We calculate terms in parentheses: -(-v+3(v-10)), so:

-v+3(v-10)

We add all the numbers together, and all the variables

-1v+3(v-10)

We multiply parentheses

-1v+3v-30

We add all the numbers together, and all the variables

2v-30

Back to the equation:

-(2v-30)



We add all the numbers together, and all the variables

-(2v-30)+32=0

We get rid of parentheses

-2v+30+32=0

We add all the numbers together, and all the variables

-2v+62=0

We move all terms containing v to the left, all other terms to the right

-2v=-62

v=-62/-2

v=+31

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