2(5x)+4(36)-10x=(-4)(6x+4)+16

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Solution for 2(5x)+4(36)-10x=(-4)(6x+4)+16 equation: 



2(5x)+4(36)-10x=(-4)(6x+4)+16

We move all terms to the left:

2(5x)+4(36)-10x-((-4)(6x+4)+16)=0

We add all the numbers together, and all the variables

15x-((-4)(6x+4)+16)+436=0

We multiply parentheses ..

15x-((-24x-16)+16)+436=0



We calculate terms in parentheses: -((-24x-16)+16), so:

(-24x-16)+16

We get rid of parentheses

-24x-16+16

We add all the numbers together, and all the variables

-24x

Back to the equation:

-(-24x)



We get rid of parentheses

15x+24x+436=0

We add all the numbers together, and all the variables

39x+436=0

We move all terms containing x to the left, all other terms to the right

39x=-436

x=-436/39

x=-11+7/39

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