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2(5x)=160-(5x-5)
We move all terms to the left:
2(5x)-(160-(5x-5))=0
We calculate terms in parentheses: -(160-(5x-5)), so:We get rid of parentheses
160-(5x-5)
determiningTheFunctionDomain -(5x-5)+160
We get rid of parentheses
-5x+5+160
We add all the numbers together, and all the variables
-5x+165
Back to the equation:
-(-5x+165)
25x+5x-165=0
We add all the numbers together, and all the variables
30x-165=0
We move all terms containing x to the left, all other terms to the right
30x=165
x=165/30
x=5+1/2
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