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2(5x+-1)=3(x+11)
We move all terms to the left:
2(5x+-1)-(3(x+11))=0
We add all the numbers together, and all the variables
2(5x-1)-(3(x+11))=0
We multiply parentheses
10x-(3(x+11))-2=0
We calculate terms in parentheses: -(3(x+11)), so:We get rid of parentheses
3(x+11)
We multiply parentheses
3x+33
Back to the equation:
-(3x+33)
10x-3x-33-2=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5
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