2(5x+1)=6(33-10x)

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Solution for 2(5x+1)=6(33-10x) equation: 



2(5x+1)=6(33-10x)

We move all terms to the left:

2(5x+1)-(6(33-10x))=0

We add all the numbers together, and all the variables

2(5x+1)-(6(-10x+33))=0

We multiply parentheses

10x-(6(-10x+33))+2=0



We calculate terms in parentheses: -(6(-10x+33)), so:

6(-10x+33)

We multiply parentheses

-60x+198

Back to the equation:

-(-60x+198)



We get rid of parentheses

10x+60x-198+2=0

We add all the numbers together, and all the variables

70x-196=0

We move all terms containing x to the left, all other terms to the right

70x=196

x=196/70

x=2+4/5

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