2(5x+2)+3(3x+4)+3=19x+20

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Solution for 2(5x+2)+3(3x+4)+3=19x+20 equation:


Simplifying
2(5x + 2) + 3(3x + 4) + 3 = 19x + 20

Reorder the terms:
2(2 + 5x) + 3(3x + 4) + 3 = 19x + 20
(2 * 2 + 5x * 2) + 3(3x + 4) + 3 = 19x + 20
(4 + 10x) + 3(3x + 4) + 3 = 19x + 20

Reorder the terms:
4 + 10x + 3(4 + 3x) + 3 = 19x + 20
4 + 10x + (4 * 3 + 3x * 3) + 3 = 19x + 20
4 + 10x + (12 + 9x) + 3 = 19x + 20

Reorder the terms:
4 + 12 + 3 + 10x + 9x = 19x + 20

Combine like terms: 4 + 12 = 16
16 + 3 + 10x + 9x = 19x + 20

Combine like terms: 16 + 3 = 19
19 + 10x + 9x = 19x + 20

Combine like terms: 10x + 9x = 19x
19 + 19x = 19x + 20

Reorder the terms:
19 + 19x = 20 + 19x

Add '-19x' to each side of the equation.
19 + 19x + -19x = 20 + 19x + -19x

Combine like terms: 19x + -19x = 0
19 + 0 = 20 + 19x + -19x
19 = 20 + 19x + -19x

Combine like terms: 19x + -19x = 0
19 = 20 + 0
19 = 20

Solving
19 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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