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2(5x+2)-3(x-4)=2(4x+5)
We move all terms to the left:
2(5x+2)-3(x-4)-(2(4x+5))=0
We multiply parentheses
10x-3x-(2(4x+5))+4+12=0
We calculate terms in parentheses: -(2(4x+5)), so:We add all the numbers together, and all the variables
2(4x+5)
We multiply parentheses
8x+10
Back to the equation:
-(8x+10)
7x-(8x+10)+16=0
We get rid of parentheses
7x-8x-10+16=0
We add all the numbers together, and all the variables
-1x+6=0
We move all terms containing x to the left, all other terms to the right
-x=-6
x=-6/-1
x=+6
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