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2(5x+2)-9x=3(x-2)-3(x-4)
We move all terms to the left:
2(5x+2)-9x-(3(x-2)-3(x-4))=0
We add all the numbers together, and all the variables
-9x+2(5x+2)-(3(x-2)-3(x-4))=0
We multiply parentheses
-9x+10x-(3(x-2)-3(x-4))+4=0
We calculate terms in parentheses: -(3(x-2)-3(x-4)), so:We add all the numbers together, and all the variables
3(x-2)-3(x-4)
We multiply parentheses
3x-3x-6+12
We add all the numbers together, and all the variables
6
Back to the equation:
-(6)
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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