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2(5x+3)-5=2(2x+10)
We move all terms to the left:
2(5x+3)-5-(2(2x+10))=0
We multiply parentheses
10x-(2(2x+10))+6-5=0
We calculate terms in parentheses: -(2(2x+10)), so:We add all the numbers together, and all the variables
2(2x+10)
We multiply parentheses
4x+20
Back to the equation:
-(4x+20)
10x-(4x+20)+1=0
We get rid of parentheses
10x-4x-20+1=0
We add all the numbers together, and all the variables
6x-19=0
We move all terms containing x to the left, all other terms to the right
6x=19
x=19/6
x=3+1/6
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