2(5x+4)+(x-4)=72

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Solution for 2(5x+4)+(x-4)=72 equation: 



2(5x+4)+(x-4)=72

We move all terms to the left:

2(5x+4)+(x-4)-(72)=0

We multiply parentheses

10x+(x-4)+8-72=0

We get rid of parentheses

10x+x-4+8-72=0

We add all the numbers together, and all the variables

11x-68=0

We move all terms containing x to the left, all other terms to the right

11x=68

x=68/11

x=6+2/11

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