2(5x+4)-7x=3(x-2)+x-10

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Solution for 2(5x+4)-7x=3(x-2)+x-10 equation: 



2(5x+4)-7x=3(x-2)+x-10

We move all terms to the left:

2(5x+4)-7x-(3(x-2)+x-10)=0

We add all the numbers together, and all the variables

-7x+2(5x+4)-(3(x-2)+x-10)=0

We multiply parentheses

-7x+10x-(3(x-2)+x-10)+8=0



We calculate terms in parentheses: -(3(x-2)+x-10), so:

3(x-2)+x-10

We add all the numbers together, and all the variables

x+3(x-2)-10

We multiply parentheses

x+3x-6-10

We add all the numbers together, and all the variables

4x-16

Back to the equation:

-(4x-16)



We add all the numbers together, and all the variables

3x-(4x-16)+8=0

We get rid of parentheses

3x-4x+16+8=0

We add all the numbers together, and all the variables

-1x+24=0

We move all terms containing x to the left, all other terms to the right

-x=-24

x=-24/-1

x=+24

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