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2(5x+4)=3(2x+1)+4x
We move all terms to the left:
2(5x+4)-(3(2x+1)+4x)=0
We multiply parentheses
10x-(3(2x+1)+4x)+8=0
We calculate terms in parentheses: -(3(2x+1)+4x), so:We get rid of parentheses
3(2x+1)+4x
We add all the numbers together, and all the variables
4x+3(2x+1)
We multiply parentheses
4x+6x+3
We add all the numbers together, and all the variables
10x+3
Back to the equation:
-(10x+3)
10x-10x-3+8=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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