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2(5x-1)=3(3x+2)+1
We move all terms to the left:
2(5x-1)-(3(3x+2)+1)=0
We multiply parentheses
10x-(3(3x+2)+1)-2=0
We calculate terms in parentheses: -(3(3x+2)+1), so:We get rid of parentheses
3(3x+2)+1
We multiply parentheses
9x+6+1
We add all the numbers together, and all the variables
9x+7
Back to the equation:
-(9x+7)
10x-9x-7-2=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9
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