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2(5x-2)+4x=2(x-20)
We move all terms to the left:
2(5x-2)+4x-(2(x-20))=0
We add all the numbers together, and all the variables
4x+2(5x-2)-(2(x-20))=0
We multiply parentheses
4x+10x-(2(x-20))-4=0
We calculate terms in parentheses: -(2(x-20)), so:We add all the numbers together, and all the variables
2(x-20)
We multiply parentheses
2x-40
Back to the equation:
-(2x-40)
14x-(2x-40)-4=0
We get rid of parentheses
14x-2x+40-4=0
We add all the numbers together, and all the variables
12x+36=0
We move all terms containing x to the left, all other terms to the right
12x=-36
x=-36/12
x=-3
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