2(5x-20)=10(x-4)

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Solution for 2(5x-20)=10(x-4) equation:


Simplifying
2(5x + -20) = 10(x + -4)

Reorder the terms:
2(-20 + 5x) = 10(x + -4)
(-20 * 2 + 5x * 2) = 10(x + -4)
(-40 + 10x) = 10(x + -4)

Reorder the terms:
-40 + 10x = 10(-4 + x)
-40 + 10x = (-4 * 10 + x * 10)
-40 + 10x = (-40 + 10x)

Add '40' to each side of the equation.
-40 + 40 + 10x = -40 + 40 + 10x

Combine like terms: -40 + 40 = 0
0 + 10x = -40 + 40 + 10x
10x = -40 + 40 + 10x

Combine like terms: -40 + 40 = 0
10x = 0 + 10x
10x = 10x

Add '-10x' to each side of the equation.
10x + -10x = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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