2(5x-3)+1=4(x+5)+6

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Solution for 2(5x-3)+1=4(x+5)+6 equation: 



2(5x-3)+1=4(x+5)+6

We move all terms to the left:

2(5x-3)+1-(4(x+5)+6)=0

We multiply parentheses

10x-(4(x+5)+6)-6+1=0



We calculate terms in parentheses: -(4(x+5)+6), so:

4(x+5)+6

We multiply parentheses

4x+20+6

We add all the numbers together, and all the variables

4x+26

Back to the equation:

-(4x+26)



We add all the numbers together, and all the variables

10x-(4x+26)-5=0

We get rid of parentheses

10x-4x-26-5=0

We add all the numbers together, and all the variables

6x-31=0

We move all terms containing x to the left, all other terms to the right

6x=31

x=31/6

x=5+1/6

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