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2(5x-3)=3(3x+2)
We move all terms to the left:
2(5x-3)-(3(3x+2))=0
We multiply parentheses
10x-(3(3x+2))-6=0
We calculate terms in parentheses: -(3(3x+2)), so:We get rid of parentheses
3(3x+2)
We multiply parentheses
9x+6
Back to the equation:
-(9x+6)
10x-9x-6-6=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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