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2(5x-3)=3(3x-2)+x
We move all terms to the left:
2(5x-3)-(3(3x-2)+x)=0
We multiply parentheses
10x-(3(3x-2)+x)-6=0
We calculate terms in parentheses: -(3(3x-2)+x), so:We get rid of parentheses
3(3x-2)+x
We add all the numbers together, and all the variables
x+3(3x-2)
We multiply parentheses
x+9x-6
We add all the numbers together, and all the variables
10x-6
Back to the equation:
-(10x-6)
10x-10x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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