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2(5x-3)=5+(4x-2)
We move all terms to the left:
2(5x-3)-(5+(4x-2))=0
We multiply parentheses
10x-(5+(4x-2))-6=0
We calculate terms in parentheses: -(5+(4x-2)), so:We get rid of parentheses
5+(4x-2)
determiningTheFunctionDomain (4x-2)+5
We get rid of parentheses
4x-2+5
We add all the numbers together, and all the variables
4x+3
Back to the equation:
-(4x+3)
10x-4x-3-6=0
We add all the numbers together, and all the variables
6x-9=0
We move all terms containing x to the left, all other terms to the right
6x=9
x=9/6
x=1+1/2
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