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2(5x-4)+x=3(x+1)-3
We move all terms to the left:
2(5x-4)+x-(3(x+1)-3)=0
We add all the numbers together, and all the variables
x+2(5x-4)-(3(x+1)-3)=0
We multiply parentheses
x+10x-(3(x+1)-3)-8=0
We calculate terms in parentheses: -(3(x+1)-3), so:We add all the numbers together, and all the variables
3(x+1)-3
We multiply parentheses
3x+3-3
We add all the numbers together, and all the variables
3x
Back to the equation:
-(3x)
8x-8=0
We move all terms containing x to the left, all other terms to the right
8x=8
x=8/8
x=1
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