2(5x-40)=ax+b

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Solution for 2(5x-40)=ax+b equation:


Simplifying
2(5x + -40) = ax + b

Reorder the terms:
2(-40 + 5x) = ax + b
(-40 * 2 + 5x * 2) = ax + b
(-80 + 10x) = ax + b

Solving
-80 + 10x = ax + b

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1ax' to each side of the equation.
-80 + -1ax + 10x = ax + -1ax + b

Combine like terms: ax + -1ax = 0
-80 + -1ax + 10x = 0 + b
-80 + -1ax + 10x = b

Add '80' to each side of the equation.
-80 + -1ax + 80 + 10x = 80 + b

Reorder the terms:
-80 + 80 + -1ax + 10x = 80 + b

Combine like terms: -80 + 80 = 0
0 + -1ax + 10x = 80 + b
-1ax + 10x = 80 + b

Reorder the terms:
-80 + -1ax + -1b + 10x = 80 + b + -80 + -1b

Reorder the terms:
-80 + -1ax + -1b + 10x = 80 + -80 + b + -1b

Combine like terms: 80 + -80 = 0
-80 + -1ax + -1b + 10x = 0 + b + -1b
-80 + -1ax + -1b + 10x = b + -1b

Combine like terms: b + -1b = 0
-80 + -1ax + -1b + 10x = 0

The solution to this equation could not be determined.

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