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2(5x=6)(23x+3/5x+6)=2(5x+6)(1/2)
We move all terms to the left:
2(5x-(6)(23x+3/5x+6))=0
Domain of the equation: 5x+6))!=0We multiply all the terms by the denominator
x∈R
2(5x-6(23x+3=0
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