2(5y-5)=100-(-6y+10)

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Solution for 2(5y-5)=100-(-6y+10) equation: 



2(5y-5)=100-(-6y+10)

We move all terms to the left:

2(5y-5)-(100-(-6y+10))=0

We multiply parentheses

10y-(100-(-6y+10))-10=0



We calculate terms in parentheses: -(100-(-6y+10)), so:

100-(-6y+10)

determiningTheFunctionDomain
-(-6y+10)+100

We get rid of parentheses

6y-10+100

We add all the numbers together, and all the variables

6y+90

Back to the equation:

-(6y+90)



We get rid of parentheses

10y-6y-90-10=0

We add all the numbers together, and all the variables

4y-100=0

We move all terms containing y to the left, all other terms to the right

4y=100

y=100/4

y=25

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