2(5z+3)+2(4z-1)=148

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Solution for 2(5z+3)+2(4z-1)=148 equation: 



2(5z+3)+2(4z-1)=148

We move all terms to the left:

2(5z+3)+2(4z-1)-(148)=0

We multiply parentheses

10z+8z+6-2-148=0

We add all the numbers together, and all the variables

18z-144=0

We move all terms containing z to the left, all other terms to the right

18z=144

z=144/18

z=8

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