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2(5z-1)-3(z+2)=3(z+1)
We move all terms to the left:
2(5z-1)-3(z+2)-(3(z+1))=0
We multiply parentheses
10z-3z-(3(z+1))-2-6=0
We calculate terms in parentheses: -(3(z+1)), so:We add all the numbers together, and all the variables
3(z+1)
We multiply parentheses
3z+3
Back to the equation:
-(3z+3)
7z-(3z+3)-8=0
We get rid of parentheses
7z-3z-3-8=0
We add all the numbers together, and all the variables
4z-11=0
We move all terms containing z to the left, all other terms to the right
4z=11
z=11/4
z=2+3/4
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