2(5z-1)-4(z+8)=(z+1)

Solution for 2(5z-1)-4(z+8)=(z+1) equation:

Simplifying
2(5z + -1) + -4(z + 8) = (z + 1)

Reorder the terms:
2(-1 + 5z) + -4(z + 8) = (z + 1)
(-1 * 2 + 5z * 2) + -4(z + 8) = (z + 1)
(-2 + 10z) + -4(z + 8) = (z + 1)

Reorder the terms:
-2 + 10z + -4(8 + z) = (z + 1)
-2 + 10z + (8 * -4 + z * -4) = (z + 1)
-2 + 10z + (-32 + -4z) = (z + 1)

Reorder the terms:
-2 + -32 + 10z + -4z = (z + 1)

Combine like terms: -2 + -32 = -34
-34 + 10z + -4z = (z + 1)

Combine like terms: 10z + -4z = 6z
-34 + 6z = (z + 1)

Reorder the terms:
-34 + 6z = (1 + z)

Remove parenthesis around (1 + z)
-34 + 6z = 1 + z

Solving
-34 + 6z = 1 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-34 + 6z + -1z = 1 + z + -1z

Combine like terms: 6z + -1z = 5z
-34 + 5z = 1 + z + -1z

Combine like terms: z + -1z = 0
-34 + 5z = 1 + 0
-34 + 5z = 1

Add '34' to each side of the equation.
-34 + 34 + 5z = 1 + 34

Combine like terms: -34 + 34 = 0
0 + 5z = 1 + 34
5z = 1 + 34

Combine like terms: 1 + 34 = 35
5z = 35

Divide each side by '5'.
z = 7

Simplifying
z = 7